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9m^2+24m+7=0
a = 9; b = 24; c = +7;
Δ = b2-4ac
Δ = 242-4·9·7
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-18}{2*9}=\frac{-42}{18} =-2+1/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+18}{2*9}=\frac{-6}{18} =-1/3 $
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